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28 January, 16:12

What is the equation of the line that passes through (4, - 1) and (-2, 3) ?

2 x+3y - 5 = 0

-2 x+3y - 5 = 0

2x-3y-5=0

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  1. 28 January, 16:26
    0
    Step-by-step explanation:

    (3+1) / (-2-4) = 4/-6 = - 2/3

    y + 1 = - 2/3 (x - 4)

    y + 1 = - 2/3x + 8/3

    y = - 2/3x + 5/3

    Multiply both sides by 3

    3y = - 2x + 5

    2x + 3y = 5

    2x + 3y - 5 = 0

    answer is A
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