2x-3y=8 - 5x+2y=13 find The x coordinate

x = - 5 and y = - 6 Steps:I will try to solve your system of equations. 2x - 3y = 8; - 5x + 2y = 13 Step: Solve 2x - 3y = 8 for x : 2x - 3y + 3y = 8 + 3y (Add 3y to both sides) 2x = 3y + 8 2x / 2 = 3y + 8 / 2 (Divide both sides by 2) x = 3/2 y + 4 Step: Substitute (3/2 y + 4) for x in - 5x + 2y = 13 : - 5x + 2y = 13 - 5 (3/2 y + 4) + 2y = 13 - 11 / 2 y - 20 = 13 (Simplify both sides of the equation) - 11 / 2 y - 20 + 20 = 13+20 (Add 20 to both sides) - 11 / 2 y = 33 - 11 / 2 y - 11 / 2 = 33 - 11 / 2 (Divide both sides by (-11) / 2) y = - 6 Step: Substitute (-6) for y in x = 3/2 y + 4 : x = 3/2 y + 4 x = 3/2 (-6) + 4 x = - 5

2x - 3y = 8

-5x + 2y = 13

Multiply the first equation by 2 and the second by 3.

2 (2x - 3y = 8)

3 (-5x + 2y = 13)

4x - 6y = 16

-15x + 6y = 39

Add the two equations.

-11x = 55

Divide each side by - 11.

x = - 5