If a normal distribution has a mean of 132 and a standard devistion of 20, what is the value that has a z score of 1.8?

The value would be 168.

The formula for a z-score is

z = (X-μ) / σ

Using our information, we have

1.8 = (X-132) / 20

Multiply both sides by 20:

1.8 (20) = ((X-132) / 20) * 20

36 = X-132

Add 132 to both sides:

36+132 = X-132+132

168 = X