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25 June, 16:07

in the function fx=a (x+2) (x-3) ^b, a and b are bothj integer constants and b is positive, find the value of x for f (x) = 0

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  1. 25 June, 16:09
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    f (x) = 0, when x = (-2) and x=3

    Step-by-step explanation:

    for a≠0 and b positive then for the function

    f (x) = a * (x+2) * (x-3) ᵇ

    f (x) = 0 when

    1) (x+2) = 0 → x = (-2)

    2) (x-3) = 0 → x=-3

    then for x=3 and x = (-2), f (x) = 0
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