According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

f (x) = (x3 - 3x + 1) 2

Question

Leticia Moon

Mathematics

13 July, 07:04

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

f (x) = (x3 - 3x + 1) 2

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Answers (1)

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Gideon · Answer 1

It should have 3 solutions.

The number of solutions depends on the term with the highest exponent.

So, in this case we have a cubic equation, there are 3 solutions.

If we have a quartic equation (4th power), there should be 4 solutions.

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?f (x) = (x3 - 3x + 1) 2

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?

f (x) = (x3 - 3x + 1) 2