3. The width and length of a rectangle are

consecutive integers. If the perimeter of

the rectangle is 142 inches, find the width

and length of the rectangle.

The dimensions of the rectangle are 35 inches by 36 inches.

Step-by-step explanation:

If the length and width are consecutive integers and L=n, then W=n+1 assuming the width is larger.

We are given the perimeter is 142 inches so: 2L+2W=142.

Substituting L=n and W=n+1 we have: 2 (n) + 2 (n+1) = 142.

Let's solve it:

2 (n) + 2 (n+1) = 142

Distribute:

2n+2n+2=142

Combine like terms:

4n+2=142

Subtract 2 on both sides:

4n=140

Divide both sides by 4:

n=140/4

n=35

Since L=n, then the length is 35 inches.

Since W=n+1, then the width is 36 inches.

The dimensions of the rectangle are 35 inches by 36 inches.

35 and 36

Step-by-step explanation:

If the smaller dimension is x, then the larger dimension is x + 1. Therefore:

2x + 2 (x + 1) = 142

2x + 2x + 2 = 142

4x = 140

x = 35

One dimension is 35, and the other dimension is 36.