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30 May, 06:48

The sum of two numbers is 43. One number is five less than three times the other number. What is the largest number?

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Answers (2)
  1. 30 May, 06:56
    0
    31 is greater

    Step-by-step explanation:

    I will solve your system by substitution.

    x=3y-5; 43=x+y

    Step: Solve x=3y-5 for x:

    Step: Substitute 3y-5for x in 43=x+y:

    43=x+y

    43=3y-5+y

    43=4y-5 (Simplify both sides of the equation)

    43+-4y=4y-5+-4y (Add - 4y to both sides)

    -4y+43=-5

    -4y+43+-43=-5+-43 (Add - 43 to both sides)

    -4y=-48

    (Divide both sides by - 4)

    y=12

    Step: Substitute12foryinx=3y-5:

    x=3y-5

    x = (3) (12) - 5

    x=31 (Simplify both sides of the equation)

    Answer:

    x=31 and y=12

    31 is greater than 12
  2. 30 May, 07:12
    0
    31

    Step-by-step explanation:

    Let the numbers be x and y.

    "The sum of two numbers is 43." gives us the first equation.

    x + y = 43

    "One number is five less than three times the other number." gives us the second equation.

    y = 3x - 5

    Now we solve the system of two equations below.

    x + y = 43

    y = 3x - 5

    Since the second equation is already solved for y, we will use the substitution method. We substitute 3x - 5 for y in the first equation.

    x + y = 43

    x + 3x - 5 = 43

    4x - 5 = 43

    4x = 48

    x = 12

    The first number is 12. Now we find the second number.

    x + y = 43

    12 + y = 43

    y = 31

    The larger number is 31.
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