Prove the following 1 - sin A sin (90-1) / cot (90-a) = sin^2 A

Question

Royce Sharp

Mathematics

17 April, 15:40

Prove the following 1 - sin A sin (90-1) / cot (90-a) = sin^2 A

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Damarion Farmer · Answer 1

Im going to assume its (90 - A) so we have:-

1 - sinA sin (90 - A) / cot (90 - A)

Convert to sines and cosines:-

= 1 - (sin A cos A) / cos (90 - A) / sin (90 - A)

= 1 - (sin A cos A) / sin A / cos A

= 1 - cos^2 A

= sin^2 A which is what is required.