Solve for x.

-15x+60<105 and 14x+11<-31

A). x<-3

B). x>-3

C). x=-3

D). there are no solutions

E). all caluse of x are dolutions

Question

Evelin

Mathematics

28 November, 08:10

Solve for x.

-15x+60<105 and 14x+11<-31

A). x<-3

B). x>-3

C). x=-3

D). there are no solutions

E). all caluse of x are dolutions

+2

Answers (2)

Know the Answer?

Baby Cakes · Answer 1

c.=-3 is the correct answer I just did the test

Jayden Daniels · Answer 2

-15x+60<105 and 14x+11<-31

-15x+60<105 subtract 60 from each side

-15x <45

divide by - 15 (flips the inequality)

x>3

14x+11<-31

subtract 11 from each side

14x < - 42

divide by 14

x<-3

Answer : there are no solutions since x>3 and x<-3 they are mutually exclusive (they both can't happen at the same time)

Solve for x.-15x+60<105 and 14x+11<-31A). x<-3B). x>-3C). x=-3D). there are no solutionsE). all caluse of x are dolutions

Solve for x.

-15x+60<105 and 14x+11<-31

A). x<-3

B). x>-3

C). x=-3

D). there are no solutions

E). all caluse of x are dolutions