The projectile motion of an object can be modeled using h (t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h (t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is - 9.8 m/s2. An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters. Which solution can be simplified to determine when the object will hit the ground?

Question

Ariella

Mathematics

31 May, 10:22

The projectile motion of an object can be modeled using h (t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h (t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is - 9.8 m/s2. An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters. Which solution can be simplified to determine when the object will hit the ground?

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Answers (2)

Know the Answer?

Aaron Charles · Answer 1

The answer is C. on ed gen

Koen Cherry · Answer 2

The given:

Initial velocity of 20 m/s

Initial height of 60 m

Acceleration due to gravity of - 9.8 m/s^2

Original formula:

H (t) = gt2 + v0t + h0

Derivation:

T = gt2 + v0t + h0 / h; where the yielding result will reveal the time when the object will reach the ground.