F (x) = (x+2) ^2 - 1

Find x intercept

Find y intercept

Find vertex

The x intercept occurs when y = 0.

0 = (x+2) ^2 - 1

1 = (x+2) ^2

Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.

1=x+2

-1=x

The x intercept is - 1.

The y intercept occurs when x=0.

y = (0+2) ^2 - 1

y=2^2 - 1

y=4-1

y=3

The y intercept is 3.

Now, to find the vertex ...

This parabola is currently in a format called the vertex form, which is:

f (x) = (x-h) ^2 + k

where (h, k) is the vertex.

Therefore, the vertex is (-2, - 1).