Find all solutions to 4sin (5x) = 4 between 0 and 360°. (Give your answer in degrees.)

when n=0, x=18°

when n=1, x = 90°

when n=2 x=18+72*2=162°

when n=3, x=18+72*3=234°

when n=4, x=18+72*4=306°

or

x = 18 + 72n, when n={0,1,2,3,4}

Step-by-step explanation:

4sin (5x) = 4

sin (5x) = 1

sin (α) = 1, when α=90° + 360n

5x = 90° + 360n

x = 18 + 72n

when n=0, x=18°

when n=1, x = 90°

when n=2 x=18+72*2=162°

when n=3, x=18+72*3=234°

when n=4, x=18+72*4=306°

when n=5, x°=18+72*5 = 378°

General answer : x = 18 + 72n, when n={0,1,2,3,4}