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Find the quotient of the quantity 4 times x to the 3rd power times y plus 12 times x to the 2nd power times y to the 3rd power minus 20 times x times y all over 4 times x times y. x2 + 3xy2 + 5

x2 + 3xy - 5

4x3y + 12x2y3 - 5

x2 + 3xy2 - 5

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  1. 9 July, 18:33
    0
    We have to find the quotient:

    (4 x³ y + 12 x² y³ - 20 x y) / (4 x y) =

    = 4 x y (x² + 3 x y² - 5) / (4 x y) = (Then 4 x y will be cancelled)

    = x² + 3 x y² - 5

    Answer:

    D) x² + 3 x y² - 5
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