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24 December, 18:12

The product of two consecutive even integers is 10 less than 5 times their sum. Find two integers

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Answers (2)
  1. 24 December, 18:29
    0
    X (x+2) = 5 (x+x+2) - 10

    x^2+2x=10x+10-10

    x^2-8x=0

    x (x-8)

    The answer is 0 and/or 8.
  2. 24 December, 18:39
    0
    Let one of the numbers be x

    The other number is x + 2

    x (x + 2) = 5 (x + x + 2) - 10

    x² + 2x = 10x + 10 - 10

    x² - 8x = 0

    x (x - 8) = 0

    x = 0 or x = 8

    x = 8,

    x + 2 = 10

    Answer: The numbers are 8 and 10.
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