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26 September, 07:37

Given that g (x) = 2x^2-5x+5Am , find each of the following.

a) g (0)

b) g ( - 1 )

c) g (4 )

d) g (- x)

e) g (1-t)

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  1. 26 September, 07:40
    0
    A) g (0) = 2 (0) ^2-5 (0) + 5 / / g (0) = 5

    b) g (-1) = 2 (-1) ^2-5 (-1) + 5 / / g (-1) = 14

    c) g (4) = 2 (4) ^2-5 (4) + 5 / / g (4) = 49

    d) g (-x) = 2 (-x) ^2-5 (-x) + 5 / / g (-x) = 9x+5

    e) g (1-t) = 2 (1-t) ^2-5 (1-t) + 5 / / g (1-t) = 4t^2-3t+4
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