Ask Question
24 February, 15:34

The average mark of candidate in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102,152. What is the average of the extracted scores t hat are extreme values (outliers) ?

+1
Answers (1)
  1. 24 February, 16:03
    0
    Step-by-step explanation:

    Given that : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

    The objective here is to determine the average of the extracted scores that are the extreme values (outliers)

    NOW:

    The average marks of candidates in an aptitude test was 128.5

    i. e the Mean = 128.5

    Standard Deviation = 8.2

    outlier will be outsides;

    then the range will be Mean ± 3 * SD

    = 128.5 ± 8.2 * 3

    = 128.5 ± 24.6

    Range is (103.9, 153.1)

    102 is outside this range

    Hence, the average of the extracted scores that are extreme values (outliers) will be 102 only
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The average mark of candidate in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers