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21 April, 16:35

The length of a rectangle is 3cm more than twice it's width. Find the largest possible length if the perimeter is at most 66cm

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  1. 21 April, 16:36
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    l = 3 + 2w

    2l + 2w = perimeter

    66 = 2 (3 + 2w) + 2w

    2 * 3 = 6

    2 * 2w = 4w

    6 + 4w + 2w = 66

    4w + 2w = 6w

    6 + 6w = 66

    -6

    6w = 60

    /6

    w = 10

    Width = 10

    l = 3 + 2 * 10

    2 * 10 = 20

    20 + 3 = 23

    23 = l

    23 * 2 + 10 * 2

    46 + 20 = 66

    The largest possible length is 23cm.

    The largest possible total length is 46cm.
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