Solve the rational equation 5 divided by x equals quantity 4 times x plus 1 end quantity divided by x squared, and check for extraneous solutions.

x = 1; x = 0 is an extraneous solution

x = 0; x = 1 is an extraneous solution

x = - 1; x = 0 is an extraneous solution

x = 0; x = - 1 is an extraneous solution

Question

Andreas Pennington

Mathematics

7 August, 02:23

Solve the rational equation 5 divided by x equals quantity 4 times x plus 1 end quantity divided by x squared, and check for extraneous solutions.

x = 1; x = 0 is an extraneous solution

x = 0; x = 1 is an extraneous solution

x = - 1; x = 0 is an extraneous solution

x = 0; x = - 1 is an extraneous solution

+5

Answers (1)

Know the Answer?

Kamari Le · Answer 1

x = 1, x = 0 is extraneous.

Step-by-step explanation:

5/x = 4x + 1 / x^2

5x^2 = 4x^2 + x

5x^2 - 4x^2 - x = 0

x^2 - x = 0

x (x - 1) = 0

x = 0, 1.

x is not a solution because 5/x is undefined.