A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the

spring push when you compress it from 40 cm long down to 15 cm long?

Question

Lewis

Mathematics

29 August, 05:06

A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the

spring push when you compress it from 40 cm long down to 15 cm long?

+1

Answers (1)

Know the Answer?

Ximena · Answer 1

Hooke's Law Formula:

F = k * x

•F = Force

•K = Spring Constant

•X = spring variation

Answer:

F = ?

K = 70 N/m

X = 40cm - 15cm (ending length - starting length).

But we need to change 'cm' to 'm', so we will divide the result of X by 100.

X = 25/100 → 0.25m

F = 0.25 * 70

F = 17.5 N

- mbsilvaf

A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does thespring push when you compress it from 40 cm long down to 15 cm long?

A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the

spring push when you compress it from 40 cm long down to 15 cm long?