The length of a rectangle is 6 yd more

than 3 times its width. Find the length

and the area of the rectangle given that

its perimeter is 44 yd.

The area of the rectangle is 72 yd^2. the length is represented by 3w+6. the perimeter equation is 2l+2w, so you would plug in 2 (3w+6) + 2w=44. once you solve that, w=4. plug in 4 into 3w+6 and you would get 18 for the length. area is lw, so 18 (4) is 72