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30 June, 15:43

The numbers 1 through 10 are recorded on individual slips of paper and placed in a hat. what is the probability of drawing the 3, not replacing it, and then drawing the 7?

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  1. 30 June, 15:49
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    The answer is 1/10*1/9=1/90
  2. 30 June, 15:55
    0
    First you have to determine the probability of drawing a 3 from the original 10 options. You do this by take the 1 outcome you desire and divide it by all the options available:

    1/10 = 0.1

    Now you need to determine the probability of obtaining the 7 from the remaining 9 options. You do this by taking the 1 outcome you desire from the and divide it by all the options available, which due to the fact that we've already taken 1 number out our remaining options are limited to 9 numbers:

    1/9 = 0.11

    Now add the 2 probabilities together to determine the probability of getting a 3 and then a 7.

    0.1 + 0.11 = 0.21, which means the probability is 21%.
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