Solve the problem.

A rain gutter is made from sheets of aluminum that are 25 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 50 square inches. There are two solutions to this problem. Round to the nearest tenth of an inch.

A) 2.5 in. and 10.0 in.

B) 2.2 in. and 22.8 in.

C) 3.0 in. and 12.0 in.

D) 1.8 in. and 18.2 in.

Question

Osborn

Mathematics

7 July, 02:44

Solve the problem.

A rain gutter is made from sheets of aluminum that are 25 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 50 square inches. There are two solutions to this problem. Round to the nearest tenth of an inch.

A) 2.5 in. and 10.0 in.

B) 2.2 in. and 22.8 in.

C) 3.0 in. and 12.0 in.

D) 1.8 in. and 18.2 in.

+5

Answers (2)

Know the Answer?

Cruz Gallegos · Answer 1

The right option is A.

Darwin · Answer 2

Imagine a 'U' shape

sides are x legnth

base is b legnth

2x+b=25

area is height times base=xb

xb=50

2x+b=25

solve

minus 2x both sides

b=25-2x

sub for b

x (25-2x) = 50

25x-2x^2=50

times - 1 both sides

2x^2-25x=-50

add 50 both sides

2x^2-25x+50=0

use quadratic formula or something

x=2.5 or 10

A is the answer