Spiderman, whose mass is 70.0 kg, is dangling on the free end of a 12.2-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a θ = 58.4° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver?

Question

Kylee Collins

Physics

27 July, 02:40

Spiderman, whose mass is 70.0 kg, is dangling on the free end of a 12.2-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a θ = 58.4° angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver?

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Answers (1)

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Macias · Answer 1

U = - 3978.8 J

Explanation:

The work of the gravitational force U just depends of the heigth and is calculated as:

U = - mgh

Where m is the mass, g is the gravitational acceleration and h the alture.

for calculate the alture we will use the following equation:

h = L-Lcos (θ)

Where L is the large of the rope and θ is the angle.

Replacing dа ta:

h = 12.2-12.2cos (58.4)

h = 5.8 m

Finally U is equal to:

U = - 70 (9.8) (5.8)

U = - 3,978.8 J