If the vertical component of velocity for a projectile is 7.3 meters/second, find its hang time.

The height of the projectile is given by:

h = ut - 0.5at²

The height will be 0 twice, once at t = 0 and the second time at the time when the journey has been completed, or t = hang time.

0 = 7.3t - 0.5 (9.81) t²

t = 1.49 seconds