A 1.2x10^3 kilogram car is accelerated uniformly from 10. meters per second to 20 meters per second in 5.0 seconds. what is the magnitude of the net force acting on the car during this 5.0 second interval

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Brogan Vargas

Physics

26 December, 06:43

A 1.2x10^3 kilogram car is accelerated uniformly from 10. meters per second to 20 meters per second in 5.0 seconds. what is the magnitude of the net force acting on the car during this 5.0 second interval

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Soren Walls · Answer 1

Force, F = ma

F = m (v - u) / t

Where m = mass in kg, v = final velocity in m/s, u = initial velocity in m/s

t = time, Force is in Newton.

m = 1.2*10³ kg, u = 10 m/s, v = 20 m/s, t = 5s

F = 1.2*10³ (20 - 10) / 5

F = 2.4*10³ N = 2400 N