A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J / (kg * K) B. 383 J / (kgK) C. 130 J / (kg K) D. 897 J / (kg*K)

Question

Jonathon Schroeder

Physics

11 March, 15:33

A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J / (kg * K) B. 383 J / (kgK) C. 130 J / (kg K) D. 897 J / (kg*K)

+4

Answers (1)

Know the Answer?

Devin Smith · Answer 1

Answer is D. The formula is Q=c*m*delta T. To raise m kg of substance with specific heat c by T kelvin, we need Q J of heat. Rearrange the equation, c=Q / (m*delta T). Plug in our numbers, Q=3.59kJ=3590J, m=0.200, T=20.0, c=3590 / (0.200*20.0) = 897 J (kg*K).

A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J / (kg * K) B. 383 J / (kg*K) C. 130 J / (kg * K) D. 897 J / (kg*K)

A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J / (kg * K) B. 383 J / (kgK) C. 130 J / (kg K) D. 897 J / (kg*K)