A particle is acted on by two torques about the origin: vector tau1 has a magnitude of 1.8 N · m and is directed in the positive direction of the x axis, and vector tau2 has a magnitude of 4.8 N · m and is directed in the negative direction of the y axis. What are the magnitude and direction of dl with arrow/dt, where l with arrow is the angular momentum of the particle about the origin?

Question

Jovanni Crawford

Physics

25 December, 17:52

A particle is acted on by two torques about the origin: vector tau1 has a magnitude of 1.8 N · m and is directed in the positive direction of the x axis, and vector tau2 has a magnitude of 4.8 N · m and is directed in the negative direction of the y axis. What are the magnitude and direction of dl with arrow/dt, where l with arrow is the angular momentum of the particle about the origin?

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Answers (1)

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Kelvin Pacheco · Answer 1

5,126 N*m

Explanation:

Since the magnitudes are vectors, the Pythagoras theorem can be used to find the resulting vector ((1,8^2 + 4,8^2) ^1/2). The direction of this vector will be contained in the X-Y plane, specifically in the fourth quadrant in Cartesian coordinates.