Use g = 9.8 m/s2. From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.7 m/s. (a) What is the acceleration (magnitude in m/s2 and direction) of the stone while it moves downward, after leaving the person's hand?

Question

Deshawn Wilson

Physics

10 July, 22:08

Use g = 9.8 m/s2. From the top of a cliff, a person throws a stone straight downward. The initial speed of the stone just after leaving the person's hand is 9.7 m/s. (a) What is the acceleration (magnitude in m/s2 and direction) of the stone while it moves downward, after leaving the person's hand?

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Korbin Stephens · Answer 1

9.8 m/s² downward

Explanation:

Any freely falling body whether started from rest or with some initial velocity has the same acceleration i. e., the acceleration due to gravity g = 9.8 m/s².

The stone which is thrown with a higher velocity may have the final velocity greater than the final velocity of the stone thrown from rest.

If a stone is thrown with a velocity then the time taken to reach the ground will be less compared to a stone falling from rest.

In both the cases the acceleration due to gravity will be the same.