A car is moving on the distance 35km in the time 30minutes, stays 20 minutes, the it moves again vith the velocite 60km/h in 25 minutes:

a) The first velocity on the first part of the road

b) The distance driven on the last part of the road

c) The average velocity in meters/seconds

Question

Jamir Bradshaw

Physics

19 March, 20:26

A car is moving on the distance 35km in the time 30minutes, stays 20 minutes, the it moves again vith the velocite 60km/h in 25 minutes:

a) The first velocity on the first part of the road

b) The distance driven on the last part of the road

c) The average velocity in meters/seconds

+4

Answers (1)

Know the Answer?

Manuel Hutchinson · Answer 1

Velocity = distance/time

v = (35) / (1/2)

v = 70 km/h

60 km/h for 25 minutes

25 minutes = 25/60 hour

distance = velocity * time

d = (60) * (25/60)

d = 25 km

ΔV = { V (initial) - V (final) } / time

v = (70-60) / (45/60)

average velocity = 13.33 km/h

avg veloticy = 3.7 m/s

A car is moving on the distance 35km in the time 30minutes, stays 20 minutes, the it moves again vith the velocite 60km/h in 25 minutes:a) The first velocity on the first part of the roadb) The distance driven on the last part of the roadc) The average velocity in meters/seconds

A car is moving on the distance 35km in the time 30minutes, stays 20 minutes, the it moves again vith the velocite 60km/h in 25 minutes:

a) The first velocity on the first part of the road

b) The distance driven on the last part of the road

c) The average velocity in meters/seconds