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23 July, 15:53

It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 23.0°C to 68.0°C. What is the specific heat of benzene?

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  1. 23 July, 16:06
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    1716.475 J/kg.°C.

    Explanation:

    Specific Heat capacity is given as

    Q = cm (t₂-t₁) ... Equation 1

    Where Q = quantity of heat, c = specif heat of benzene, m = mass of benzene, t₁ = initial temperature, t₂ = final temperature.

    Make c the subject of the equation,

    c = Q/m (t₂-t₁) ... Equation 2

    Given: Q = 11.2 kJ = 11200 J m = 145 g = 0.145 kg, t₂ = 68.0°C, t₁ = 23.0°C

    Substitute into equation 2.

    c = 11200/[0.145 (68-23) ]

    c = 11200/6.525

    c = 1716.475 J/kg.°C.

    Hence the specific heat of benzene = 1716.475 J/kg.°C.
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