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2 December, 20:42

A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash.

a) how far does the sprinter travel during the first 6 seconds?

b) how much farther does the sprinter have to travel to reach the finish line?

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  1. 2 December, 20:58
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    a) 36 m

    b) 64 m

    Explanation:

    Given:

    v₀ = 0 m/2

    v = 12 m/s

    t = 6 s

    Find: Δx

    Δx = ½ (v + v₀) t

    Δx = ½ (12 m/s + 0 m/s) (6 s)

    Δx = 36 m

    The track is 100 m, so the sprinter still has to run another 64 m.
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