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30 January, 12:46

If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in calories and joules)

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  1. 30 January, 12:54
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    For the answer to the question above,

    Q = amount of heat (kJ)

    cp = specific heat capacity (kJ/kg. K) = 4.187 kJ/kgK

    m = mass (kg)

    dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin

    Q = 100kg * (4.187 kJ/kgK) * 15 K

    Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal
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