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7 February, 20:46

A ball is thrown at an angle of 40° above the horizontal at a speed of 16.0 m/s from the top of a 12.4 m tall building. What is the maximum height of the ball above the ground?

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  1. 7 February, 20:59
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    What you do is, multiply 16.0 and 12.4 together. then multiply that by 40a
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