A 1200-N crate rests on the floor. How much work is required to move it at constant speed (a) 5.0 m along the floor against a friction force of 230 N, and (b) 5.0 m vertically?

Question

Dominique Glenn

Physics

18 July, 08:15

A 1200-N crate rests on the floor. How much work is required to move it at constant speed (a) 5.0 m along the floor against a friction force of 230 N, and (b) 5.0 m vertically?

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Answers (1)

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Eric · Answer 1

(a) The work required to move the crate = 7150 J

(b) The Work required to move the crate vertically = 6000 J

Explanation:

(a) Frictional Force: These is the force that tend to oppose the motion of two bodies in contact.

Work required to move the crate = work done against friction + work required to move it through a distance of 5.0 m.

Wr = Wf + Wd

Where Wr = work required to move the crate, Wf = work done against friction, Wd = work required to move the crate through 5.0 m

Given: Wf = friction force * distance = 230*5 = 1150 J

and Wd = force * distance = 1200*5.0 = 6000 J.

Substituting these values into equation 1

Wr = 6000 + 1150

Wr = 7150 J

Therefore the work required to move the crate = 7150 J

(b)

Work required to move the crate vertically = mgh

or

Work required to move the crate vertically = Wh ... Equation 2

Where W = weight of the block, h = vertical height

Given:W = 1200 N, h = 5.0 m

Substituting these values into equation 2

Work required to move the crate vertically = 1200*5

Work required to move the crate vertically = 6000 J