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21 April, 09:15

A quarterback throws a pass at an angle of 35◦ above the horizontal with an initial speed of 25 m/s. the receiver catches the ball 2.55 s later. determine the distance the ball was thrown.

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  1. 21 April, 09:43
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    As this is the projectile motion means the motion of object under constant acceleration, so we use all eq. of motion under constant acceleration.

    Angle above horizontal=θ = 35°

    Initial speed = v₁ = 25 m/s

    Time of flight = t = 2.55 s

    Now,

    from eq. of motion

    x=x₁ + (v₁*cosθ) (t) + 1/2 * a*t²

    As, there is no acceleration in horizontal direction so a=0 and also initial displacement x₁=0

    x = 25*cos (35) * 2.55

    x=52.22 m
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