A dump truck accelerates uniformly from a resting position to a velocity of 35 m/s north in 20 seconds. What is the displacement?

a.) 1.75 m north

b.) 61.25 m north

c.) 350 m north

d.) 700 m north

As this is a straight-line motion problem, the following formulas will be used to solve for acceleration, which is used to solve for displacement:

Vf = Vi + a * t

s = Vi * t + 1/2 (a*t^2)

Where: Vf = final velocity

Vi = initial velocity

a = acceleration

t = time

s = displacement

Using eq. 1:

35 m/s = 0 m/s + a * 20 s

a = 35 / 20

a = 1.75 m/s^2

Using eq. 2:

s = 0 * 20 + 1/2 (1.75 * 20^2)

s = 350 m

Therefore, the correct answer is C.