A solid cylinder of mass 7 kg and radius 0.9 m starts from rest at the top of a 20º incline. It is released and rolls without slipping to the bottom of the incline. Assume g = 9.81 m/s2. If the difference in height between the top of the incline and the bottom is 2.3 m, the total energy of the cylinder at the bottom is:

Question

Caroline West

Physics

14 February, 06:28

A solid cylinder of mass 7 kg and radius 0.9 m starts from rest at the top of a 20º incline. It is released and rolls without slipping to the bottom of the incline. Assume g = 9.81 m/s2. If the difference in height between the top of the incline and the bottom is 2.3 m, the total energy of the cylinder at the bottom is:

+4

Answers (1)

Know the Answer?

Larson · Answer 1

157.8 J

Explanation:

m = mass of the cylinder = 7 kg

h = height difference in top and bottom of the incline = 2.3 m

g = acceleration due to gravity = 9.8 m/s²

TE = Total Energy at the bottom

PE = Gravitational potential energy at the top

Using conservation of energy

Total Energy at the bottom = Gravitational potential energy at the top

TE = PE

TE = m g h

TE = (7) (9.8) (2.3)

TE = 157.8 J