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29 December, 18:55

A spacecraft of mass 1500 kg orbits the earth at an altitude of approximately 450 km above the surface of the earth. Assuming a circular orbit, what is the attractive force that the earth exerts to keep the spacecraft + in orbit? Answer: (a) 1.28x 10^7 (N) (b) 2.99 x 10^7 (N) (c) 3.56 x 10^7 (N). (d) 4.11 x 10^7 (N) (e) 5.06x 10^7 (N)

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  1. 29 December, 19:06
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    1.28 x 10^4 N

    Explanation:

    m = 1500 kg, h = 450 km, radius of earth, R = 6400 km

    Let the acceleration due to gravity at this height is g'

    g' / g = {R / (R + h) }^2

    g' / g = {6400 / (6850) }^2

    g' = 8.55 m/s^2

    The force between the spacecraft and teh earth is teh weight of teh spacecraft

    W = m x g' = 1500 x 8.55 = 1.28 x 10^4 N
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