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1 June, 23:55

A cylindrical bucket, open at the top, is 28.0 cm high and 11.0 cm in diameter. A circular hole with a cross-sectional area 1.55 cm2 is cut in the center of the bottom of the bucket. Water flows into the bucket from a tube above it at the rate of 2.46*10-4 m3/s. Part A How high will the water in the bucket rise

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  1. 2 June, 00:22
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    so height is 0.1283 m

    Explanation:

    given data

    height = 28 cm

    diameter = 11 cm

    cross-sectional area = 1.55 cm2

    water flow rate = 2.46*10^-4 m3/s

    to find out

    How high will the water in the bucket rise

    solution

    we know that here

    potential energy = kinetic energy

    mgh = 1/2 mv²

    multiply both sides by the 2 and we get

    2mgh=mv²

    solve it we get

    √ (2gh) = v ... 1

    h = v²/2g ... 2

    and

    flow rate = A V

    2.46*10^-4 = V 1.55*10^-4

    V = 1.5870 m/s

    so from 2

    h = v²/2g

    h = 1.5870² / 2 (9.81)

    h = 0.1283 m

    so height is 0.1283 m
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