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15 August, 23:41

Calculate the number of moles in the 2.00-l volume of air in the lungs of the average person. note that the air is at 37.0ºc (body temperature).

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  1. 15 August, 23:44
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    To answer this item, we assume that the air is an ideal gas such that it follows the equation,

    PV = nRT

    The pressure of the lungs of the person should be in equilibrium to that of the surrounding, making it 1 atm. Substituting the known values to the equation,

    n = (1 atm) (2L) / (0.0821 L. atm/mol. K) (37 + 273.15)

    n = 0.0785 moles

    Answer: 0.0785 moles
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