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23 January, 08:09

A force of 32.5N stretches a spring of 0.500cm. What force will stretch a similar spring 1.60 cm?

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  1. 23 January, 08:29
    0
    104 N

    Explanation:

    Calculate the spring stiffness:

    F = kx

    32.5 N = k (0.500 cm)

    k = 65 N/cm

    Find the force for the new length:

    F = kx

    F = (65 N/cm) (1.60 cm)

    F = 104 N
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