A 900 kg steel beam is supported by the two ropes shown in (Figure 1). Calculate the tension in the rope.

Let T1 and T2 be tension in ropes1 and 2 respectively.

since system is stationary (equilibrium), considering both ropes + beam as a system

for horizontal equilibrium (no movement in that direction, so resultant force must be zero horizontally)

T1sin (20) = T2sin (30)

=> T1 = T2sin (30) / sin (20)

for vertical equilibrium, (no movement in this direction, so resultant force must be zero vertically)

T1cos (20) + T2cos (30) = mg

m = 900kg, substituting for T1

T2sin (30) * cos (20) / sin (20) + T2cos (30) = 900g

2.328*T2 = 900*9.8

T2 = 3788.65N

so T1 from (1)

T1 = 5535.21N