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31 August, 11:07

A tree branch is floating in water. The total volume of the branch is 1.12 m3 and 75.0 percent of the volume is submerged. The density of water is 1000 kg/m3. Find the buoyant force on the branch.

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  1. 31 August, 11:17
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    The buoyant force on the branch is given by:

    F = pVg

    F = buoyant force, p = water density, V = volume of branch submerged, g = gravitational acceleration

    Given values:

    p = 1000kg/m^3

    V = 0.75x1.12m^3 (75% of total volume)

    g = 9.81m/s^2

    Plug in and solve for F:

    F = 1000 (0.75x1.12) (9.81)

    F = 8240N
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