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16 October, 14:36

Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a stopwatch just as the top of the sun disappears. you then stand, elevating your eyes by a height h = 1.63 m, and stop the watch when the top of the sun again disappears. if the elapsed time is t = 10.1 s, what is the radius r of the planet to two significant figures? notice that duration of a solar day at the far-off planet is the same that is on earth. (hint: see sample problem 1-4.)

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  1. 16 October, 14:50
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    The solution for this problem is:

    In 10.1 seconds the earth rotates by 10.1 / (24*60*60) * 360 deg = 0.04208333 deg

    In that time a triangle has been created with the 2 longer sides having lengths r and r+1.95

    Cos (0.04208) = r / (r+1.95)

    = 0.999

    r (1-0.999) = 1.95*0.999

    r = 1948.05m
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