Ask Question
24 November, 14:13

A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m>s. A 1.0-kg stone is thrown from the basket with an initial velocity of 15.0 m>s per - pendicular to the path of the descending balloon, as measured relative to a person at rest in the basket. That person sees the stone hit the ground 5.00 s after it was thrown. Assume that the balloon continues its downward descent with the same constant speed of 20.0 m>s. (a) How high is the balloon when the rock is thrown

+5
Answers (2)
  1. 24 November, 14:27
    0
    Given:

    Mass = 124 kg

    U = - 20 m/s

    t = 5 s

    Using the equation of motion,

    S = U*t + 1/2 * gt^2

    S = - 20 * 5 - 1/2 * 9.8 * 5^2

    = - 222.5 m

    = 222.5 m (the sign is showing the direction of the motion from its origin)
  2. 24 November, 14:30
    0
    a) 242.5 m

    Explanation:

    Given:

    Vi = 20m/s

    t = 5 seconds

    According to kinematic equation, the displacement is given by:

    d = Vit + 1/2 gt^2

    d = 20 * 6) + (1/2 * 9.8 * 5^2)

    d = 120 + 122.5

    d = 242.5m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 20.0 m>s. A 1.0-kg stone is thrown from the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers