what will the stopping distance be a a 3000-kg car if - 3000N of force are applied when the car is traveling 10 m/s

50 m

Explanation:

Acceleration = force/mass

3000/3000=1m/s^-2

Applying equation of motion:

V^2=U^2+2as; V is final velocity, u is initial velocity, a is acceleration and s is the distance covered.

0=10^2 - 2*1s;

Solve for s