A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground?

A. 9.3m/s

B. 12m/s

C. 41m/s

D. 73m/s

Question

Miah Atkins

Physics

16 May, 19:23

A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground?

A. 9.3m/s

B. 12m/s

C. 41m/s

D. 73m/s

+5

Answers (1)

Know the Answer?

Jaylen Schneider · Answer 1

Using the kinematic equation V=Vo + at, the initial velocity (Vo) is - 32, the acceleration (a) is found by dividing force by mass 55N/.06kg=916.66 m/s/s, and the time is 0.045 sec.

V=Vo+at

V=-32+916.66*.045

V=9.25

The answer is A.

A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground?A. 9.3m/sB. 12m/sC. 41m/sD. 73m/s

A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground?

A. 9.3m/s

B. 12m/s

C. 41m/s

D. 73m/s