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16 May, 19:23

A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground?

A. 9.3m/s

B. 12m/s

C. 41m/s

D. 73m/s

+5
Answers (1)
  1. 16 May, 19:35
    0
    Using the kinematic equation V=Vo + at, the initial velocity (Vo) is - 32, the acceleration (a) is found by dividing force by mass 55N/.06kg=916.66 m/s/s, and the time is 0.045 sec.

    V=Vo+at

    V=-32+916.66*.045

    V=9.25

    The answer is A.
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Home » Physics » A 0.060 kg ball hits the ground with a speed of - 32m/s. The ball is in contact with the ground for 45 milliseconds and the ground exerts a + 55 N force on the ball. What is the magnitude of the velocity after it hits the ground? A. 9.3m/s B.
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