A 1.0 * 10^3-kilogram car travels at a constant

speed of 20. meters per second around a

horizontal circular track. The diameter of the

track is 1.0 * 10^2 meters. The magnitude of the

car's centripetal acceleration is

(1) 0.20 m/s2 (3) 8.0 m/s2

(2) 2.0 m/s2 (4) 4.0 m/s2

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Physics

24 September, 09:41

A 1.0 * 10^3-kilogram car travels at a constant

speed of 20. meters per second around a

horizontal circular track. The diameter of the

track is 1.0 * 10^2 meters. The magnitude of the

car's centripetal acceleration is

(1) 0.20 m/s2 (3) 8.0 m/s2

(2) 2.0 m/s2 (4) 4.0 m/s2

+5

Answers (1)

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Dante Bird · Answer 1

Centripetal acceleration can be calculated with the formula F=v^2/r

Substituting the values in, we get:

a=20^2/50

=8

Therefore the magnitude of the centripetal acceleration of the car is 8 ms^-2

A 1.0 * 10^3-kilogram car travels at a constantspeed of 20. meters per second around ahorizontal circular track. The diameter of thetrack is 1.0 * 10^2 meters. The magnitude of thecar's centripetal acceleration is(1) 0.20 m/s2 (3) 8.0 m/s2(2) 2.0 m/s2 (4) 4.0 m/s2

A 1.0 * 10^3-kilogram car travels at a constant

speed of 20. meters per second around a

horizontal circular track. The diameter of the

track is 1.0 * 10^2 meters. The magnitude of the

car's centripetal acceleration is

(1) 0.20 m/s2 (3) 8.0 m/s2

(2) 2.0 m/s2 (4) 4.0 m/s2