A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall.

Circle one: KE / GPE / both

The KE can be solve using the formula:

ke = 0.5 mv^2

where m is the mass of the object

v is the velocity

ke = 0.5 (2 kg) (5 m/s) ^2

ke = 25 J

the GPE can be solved using the formula:

GPE = mgh

where m is the mass

g is the acceleration due to gravity (9.81 m/s^2)

h is the height

GPE = (4 kg) (9.81 m/s^2) (40 m)

GPE = 392.4 J