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9 December, 08:34

A 6.0-g bullet leaves the muzzle of a rifle with a speed of 336 m/s. what force (assumed constant) is exerted on the bullet while it is traveling down the 0.83-m-long barrel of the rifle?

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  1. 9 December, 10:14
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    The work done on the bullet is force•distance. This is also equivalent to the energy it has leaving the muzzle (work energy theorem). This kinetic energy is (1/2) (0.006kg) (336m/s) ^2=338.7J. Then 338.7J=F•0.83m

    F=338.7/0.83=408N
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